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    right i have this question and i can only think that there are no points of intersection with the 2 lines as i cannot factorise it nor does b^2-4ac =0+...(i think)
    This is the questions...'the line y=2-3x intersects the curve X^2-y=2 at?

    Cheers
    xxxxxx
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    (Original post by Smile-Like-You-Mean-It)
    right i have this question and i can only think that there are no points of intersection with the 2 lines as i cannot factorise it nor does b^2-4ac =0+...(i think)
    This is the questions...'the line y=2-3x intersects the curve X^2-y=2 at?

    Cheers
    xxxxxx
    simultaneous equations, rearrange the first one to equal x, the second one to equal y, then substitute the first one into the second (replace x in the 2nd with whatever you arranged the 1st to)
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    (Original post by IBiot Ash '08)
    simultaneous equations, rearrange the first one to equal x, the second one to equal y, then substitute the first one into the second (replace x in the 2nd with whatever you arranged the 1st to)
    yeh i did this. But i dont think there is an intercept. Has anyone tried to work it out?
    xxxx
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    (Original post by Smile-Like-You-Mean-It)
    right i have this question and i can only think that there are no points of intersection with the 2 lines as i cannot factorise it nor does b^2-4ac =0+...(i think)
    This is the questions...'the line y=2-3x intersects the curve X^2-y=2 at?

    Cheers
    xxxxxx
    y=2-3x
    x^2-y=2

    So x^2-(2-3x)=2

    work with that.
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    "But i dont think there is an intercept."
    Well, there is because it says so in the Question:
    "y=2-3x intersects the curve"

    I don't really see the difficulty, just solve either x or y (doesn't matter which), this will give you an x or y coordinate, then substitue that value back into one of the original equations to find the x or y you didn't get first time round
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    make the second one y=x^2-2

    then x^2-2=2-3x

    then x^2+3x-4=0

    then (x+4)(x-1)
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    make the second one y=x^2-2

    then x^2-2=2-3x

    then x^2+3x-4=0

    then (x+4)(x-1)
 
 
 

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