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# Circle's Completing The Square watch

1. Right, this is going to make me sound monumentally stupid, but here goes.

Determine the centre and radius of:

2x^2 - 16x + 2y^2 + 4y = 1

(sorry for lack of latex)

All I need to know, is how to complete the square when there is a co-efficient infront of the x/y^2

Then im fine..

So far for the x part I have:

2(x-4)^2 then im stuck.

2. The band is called Circle Takes the Square and is far more interesting than this maths problem will ever be.
3. I personally just divide through by the coefficient and carry on from there:

x^2 - 8x + y^2 + 2y = 0.5
4. You don't complete the square in the same way as with quadratics. Treat the x and y parts seperately.

e.g.
5. (Original post by EasyTiger)
All I need to know, is how to complete the square when there is a co-efficient infront of the x/y^2
Since it is the same coefficient, you could divide through both sides by it
6. Thanks for both of you. The way benswellday stated was the way I was trying to do, and I got 2(x-4)^2-32 aswell. But just didnt think it was correct.

Thanks for the advice though.

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