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    I dont really understand this topic, so I'm a bit stuck on a few questions.

    I need to draw a structural isomers ( not cyclic) which has two functional groups and an ether for C3H6O. How do I do this?

    Also how amny cyclic isomers can be formed from this? 2?
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    I can think of 6 isomers of which 2 are cyclic but only one of them is a non-cyclic ether .
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    (Original post by EierVonSatan)
    I can think of 6 isomers of which 2 are cyclic but only one of them is a non-cyclic ether .
    Is the non-cyclic one CH3-CH2-OH-C
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    (Original post by definite_maybe)
    Is the non-cyclic one CH3-CH2-OH-C
    CH2=CH-O-CH3
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    (Original post by EierVonSatan)
    CH2=CH-O-CH3
    THank you. One of the cyclic isomers are oxetane with three carbons and the oxygen in a ring, but what is the second isomer? Is just the three carbons in a ring, and the H and the oxygen outside?
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    (Original post by definite_maybe)
    THank you. One of the cyclic isomers are oxetane with three carbons and the oxygen in a ring, but what is the second isomer? Is just the three carbons in a ring, and the H and the oxygen outside?
    A three membered ring with oxygen and two carbons (the other carbon on the outside of the ring)
 
 
 

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