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    I'm working my way through a practise paper but have become stuck on a certain few questions. This is them in full. Can anyone help?

    A sample of metallic americium can be made by reacting americium fluoride with barium metal at 1100 °C.

    A) Suggest a formulae for the two different ions in americium fluoride.

    B) Construct a balanced chemical equation for the reaction of barium with americium fluoride.
    Could somebody please help me with those two questions? Many thanks to anybody that reads or posts a response.
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    a) Am4+ and F-

    b) 2Ba + AmF4 ---> 2BaF2 + Am
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    Can you explain how you got these answers?

    Cheers.
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    a) Know that the most likely americium fluoride is AmIVCl4.

    b) The above + the ability to balance simple equations.
 
 
 
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