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     y= xe^2x

    find the equation of the tangent to the above curve at the point (0.5,0.5e)

    for the simplicitry of this, say i worked out dy/dx = 2

    then do we use y-y1= m(x-x1)? 



getting: [latex]y - 0.5e = 2(x - 0.5)
     y = 2x+1+ 0.5e

    where do i go from here? what do i do with the e?

    thanks
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    the curve is meant to be xe to the power of 2x, how do i put this in latex?
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    the anwer says: y = 2ex - e/2
 
 
 
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Updated: November 13, 2008

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