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# differentiate watch

1. hi

differentiate:

1)

2)

I aint done these for a while and I dont have a graphics calculator.

I'm thinkin use the chain rule for 1)

but can't figure out dy/dx for

For 2) y=e^u say, where .

so,

2. 2) Is (Root6)e^(Root6x) - Sorry can't use the code well. You just differentiate the power, then put it behind the e, keeping the power the same.

Not sure for 1... could you use the log rule to bring the power down, giving you 2ln(x^0.5), then chain rule?
3. 1) Use the power rule to differentiate y = ln(x^1/2) and then the chain rule for the actual question.

2) If u = , it does not mean unless if I've misunderstood your question.
4. ln(x^1/2) is the same as 1/2 ln(x), and ln(x) differentiates to give 1/x

And also, sqrt(6x) is the same as (sqrt6) x^1/2

Which differentiates to give 1/2(sqrt6)x^-1/2 = 1/2 sqrt(6/x)

Does that make things easier?
5. (Original post by Swayum)
1) Use the power rule to differentiate y = ln(x^1/2) and then the chain rule for the actual question.

hi, and the power rule is???

2) If u = , it does not mean unless if I've misunderstood your question.

for 2) apologies, my notation is slightly ambiguous i meant sqrt(6x) am i correct with my original answer???

best...
6. You can also do it implicitly for more lulz.
for 2) apologies, my notation is slightly ambiguous i meant sqrt(6x) am i correct with my original answer???

best...
Yup - just replace the u back in e^u.
8. ahh, many thanks peeps....the student room rocks!

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