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    A van is pushed from rest with a force of 130N over a distance of 60m. The resistivity forces acting on the van total 90N

    Using the information above how would i calculate the kinetic energy the van gains?
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    Are you given the mass of the van?
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    (Original post by JBKProductions)
    A van is pushed from rest with a force of 130N over a distance of 60m. The resistivity forces acting on the van total 90N

    Using the information above how would i calculate the kinetic energy the van gains?
    Work done = force x distance. So if you can work out the total work done by the van over the distance and subtract the work done against resistive forces, you will have the increase in kinetic energy :yep:
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    (Original post by D-Day)
    Are you given the mass of the van?
    Nope thats all ive been given
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    (Original post by sonofdot)
    Work done = force x distance. So if you can work out the total work done by the van over the distance and subtract the work done against resistive forces, you will have the increase in kinetic energy :yep:
    Or that.
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    (Original post by sonofdot)
    Work done = force x distance. So if you can work out the total work done by the van over the distance and subtract the work done against resistive forces, you will have the increase in kinetic energy :yep:
    so is it 2400 J?
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    2400 J pr 2.4 Kj
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    (Original post by JBKProductions)
    so is it 2400 J?
    Indeed
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    (Original post by jjkkll)
    2400 J pr 2.4 Kj
    ok thanks
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    (Original post by sonofdot)
    Indeed
    if you dont mind me asking another question. The resistance to the motion of a motor boat of mass 780kg is 120N, and the driving force from the propellers is 250N. What distance does it cover while increasing from 2 to 3m/s??
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    (Original post by JBKProductions)
    if you dont mind me asking another question. The resistance to the motion of a motor boat of mass 780kg is 120N, and the driving force from the propellers is 250N. What distance does it cover while increasing from 2 to 3m/s??
    I would help, but somebody negged me inexplicably on this thread... :mad:

    I'll help really This is like the opposite way around. Find the increase in the kinetic energy (E_k = \frac{1}{2}mv^2) and then the total work done equals the kinetic energy plus the work done against resistance
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    (Original post by sonofdot)
    I would help, but somebody negged me inexplicably on this thread... :mad:

    I'll help really This is like the opposite way around. Find the increase in the kinetic energy (E_k = \frac{1}{2}mv^2) and then the total work done equals the kinetic energy plus the work done against resistance
    how would i calculate the kinetic energy without the velocity or the distance it travels?
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    (Original post by JBKProductions)
    how would i calculate the kinetic energy without the velocity or the distance it travels?
    you have the velocity. The gain in kinteic energy = kinetic energy at 3m/s - kinetic energy at 2m/s
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    (Original post by sonofdot)
    you have the velocity. The gain in kinteic energy = kinetic energy at 3m/s - kinetic energy at 2m/s
    oh ok i see now i didnt understand the question properly i thought i had to work out acc and etc lol but ill try and come bk if i get stuck lol
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    (Original post by sonofdot)
    you have the velocity. The gain in kinteic energy = kinetic energy at 3m/s - kinetic energy at 2m/s
    so the kinetic energy is 1950J?
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    (Original post by sonofdot)
    I would help, but somebody negged me inexplicably on this thread... :mad:

    I was not me you crack head, at least ask before negging lol.
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    (Original post by jjkkll)
    I was not me you crack head, at least ask before negging lol.
    Ok sorry :o: I guess I miscalculated your power... not like my rep is worth anything :rolleyes:
 
 
 
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