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# Induction proof watch

1. Ok, say I have an inequality...

x_2n+1 < x_2n+3 < x_2n+4 < x_2n+2

If I prove that x_2n+1 < x_2n+2 is true, is that the same as proving the entire inequality in four terms is true? Ie if I prove

x_2n+1 < x_2n+2

I have also proven

x_2n+1 < x_2n+3 < x_2n+4 < x_2n+2

Cheers
2. Wat does x_2n mean?

coz im pretty sure that ur inequality isnt true... x_2n = k

k+1<k+3<k+4<k+2 isnt true
3. They are sequences. It is true, but it doesnt matter what the inequality is...

a < b < c < d

If I prove a < d do I consequentially prove a < b < c < d
4. (Original post by Ewan)
They are sequences. It is true, but it doesnt matter what the inequality is...

a < b < c < d

If I prove a < d do I consequentially prove a < b < c < d

imo not.
5. (Original post by Willis123)
imo not.
EDIT: No I didn't question is right.. anyway...
6. Up we go, someone must know this, its not that hard a question.
7. (Original post by Ewan)
They are sequences. It is true, but it doesnt matter what the inequality is...

a < b < c < d

If I prove a < d do I consequentially prove a < b < c < d
No, why would you? If you had a = 4 and d = 6, you could have b = and c = 20349230940234, which obviously wouldn't satisfy the inequality.

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