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    Calculate the change in the pH of water if 5cm^3 of 0.1 M nitric acid is added to 45cm^3 of water?

    Do I use ratios or something? How do I do it?
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    pH of 50cm^3 of 0.1 M HNO3 - pH of pure water

    HNO3 is a strong acid
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    (Original post by EierVonSatan)
    pH of 50cm^3 of 0.1 M HNO3 - pH of pure water

    HNO3 is a strong acid
    Wouldn't it just be the pH of 0.1M HNO3 50cm^3 - no need to take away pH of water?
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    (Original post by Hancock orbital)
    Wouldn't it just be the pH of 0.1M HNO3 50cm^3 - no need to take away pH of water?
    It's just the question asks for the ''change in pH'' on adding the acid to water (i.e. diluting it really)
 
 
 
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