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himurakenshin
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#1
Report Thread starter 14 years ago
#1
here are the questions, find dy/dx:

1)y= ln(xy-y^2)
2)y= (x+y)/(y-x)
3)y= sqrt(e^(2x-ln[x]) + (3x+y)^4)
4)y= 3(e^(x-2/y))^4

a reply as soon as possible would be most appriciated.
Thanks
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BCHL85
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#2
Report 14 years ago
#2
1) e^y = xy - y^2
e^y dy/dx = y + xdy/dx - 2y.dy/dx
--> dy/dx = ... DIY ok?
2) y^2 - xy = x+y
2ydy/dx - (y + xdy/dx) = 1 +dy/dx
--> dy/dx ... DIY
3) y^2 = e^(2x-lnx) + (3x +y)^4
2ydy/dx = (2-1/x)e^(2x-lnx) + 4(3+dy/dx)(3x+y)^3.
--> DIY, a bit harder, iam afraid
4) y/3 = e^4(x-2/y)
ln(y/3) = 4(x-2y) -> lny - ln3 = 4(x-2y)
(1/y)dy/dx =4 - 8dy/dx
-->DIY
Cheers
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