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    Could someone please take me step by step how on earth I would complete this question:
    An asset, A, has a present value of £10000 which depreciates exponentially. The value of the asset at the end of t years is given by y = 10000e-0.12t How many years (to 2dp) will it take for the asset to depreciate down to £3000?
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    I would think you intended to write 'The value of the asset at the end of t years is given by:

    y=10000e^{-0.12t}

    as this is the usual form for exponential depreciation.

    You know what y is the value after a number of years so if you want to know how long it takes to be valued at £3000 then what you have to do is substitute 3000 in for y so now you have:

    3000=10000e^{-0.12t}

    Where t is the time taken to depreciate in value to £3000.

    All you need to do now is solve it. First divide both sides by 10000 and then remember that if:

    a=e^b then  b=ln(a)

    If it was actually supposed to be

     y = 10000e - 0.12t then simply put y as 3000 and then solve the equation.

    Hope this helps
 
 
 
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