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Math Induction Question

I never got taught math induction, but here is the q i got:

For an equation y=xny=x^n, where n is positive integers:

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area B is the area under the curve from x = a to b and the x axis; and can be found the with equation 1n+1\frac {1}{n+1}

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area A is the area from y=any=a^n to y=bny=b^n and the y axis; and can be found with the equation nn+1\frac {n}{n+1}



Using mathematical induction, prove that the ratio of area A:area B is always n:1n:1 for all positive integers, as a, b and n vary


How/What exactly would you do?
Reply 1
Avatar for James
James
14
Surely Area A : Area B = 1n+1:nn+1\frac{1}{n+1}:\frac{n}{n+1} = 1:n, so the statement is false?
Reply 2
Avatar for G O D I V A
G O D I V A
OP
11
James
Surely Area A : Area B = 1n+1:nn+1\frac{1}{n+1}:\frac{n}{n+1} = 1:n, so the statement is false?



mixed the A and B up, it is infact A =nn+1\frac{n}{n+1} and B \ 1n+1 \frac{1}{n+1}

therefore, n:1
Reply 3
Avatar for Dadeyemi
Dadeyemi
13
not induction just A:B = n/(n+1):1/(n+1)= n:1
Reply 4
Avatar for G O D I V A
G O D I V A
OP
11
Thats what i thought but the question says use induction as a, b, n vary

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