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Express y in terms of x help

Basically, one of my exam questions says express y in terms of x

Q) A cone has radius 2x and height y. A sphere has radius 3x

Express y in terms of x

A) I have the answer but I do not know how they got that answer, I need to learn the method involved. please. the solution is...

1/3pi(2x)^2y=4/3pi(3x)^3
4pi x^2y=4pi(3x)^3
x^y=27x^3
y=27


Please can someone show me how they worked out that method. I get the top line of working, that's simple, I become stuck on the 2nd line, how did they get 4pi????

Thanks :smile:
Multiply both sides by 3. Then notice that (2x)^2 = 4x^2.
Reply 2
What do you meen multiply both siides by 3
Reply 3
You didn't specify - are they saying that they have equal volumes? surface areas?
Sophie Maywood
What do you meen multiply both siides by 3

Take the first line of working (the line you said you understood), and multiply the left-hand side and the right-hand side of that equation by 3.
Reply 5
Yes they both have equal volumes but why do you multiply by 3?
The have equal volume.
(2x)2yπ3=4π(3x)33 \frac {(2x)^2y\pi}{3} = \frac {4\pi(3x)^3}{3}
Both sides have a common denominator, 3, you can multiply it over, or multiply both sides by 3 as was already said, to cancel it out.
(2x)2yπ=4π(3x)3 (2x)^2y\pi = 4\pi(3x)^3
The rest is rearranging an equation.
Reply 7
It also says give your answer in its simplest form- if that helps anyone?
Reply 8
Yes but how do you rearrange?
Reply 9
Sophie Maywood
Basically, one of my exam questions says express y in terms of x

Q) A cone has radius 2x and height y. A sphere has radius 3x

Express y in terms of x

A) I have the answer but I do not know how they got that answer, I need to learn the method involved. please. the solution is...

1/3pi(2x)^2y=4/3pi(3x)^3
4pi x^2y=4pi(3x)^3
x^y=27x^3
y=27


Please can someone show me how they worked out that method. I get the top line of working, that's simple, I become stuck on the 2nd line, how did they get 4pi????

Thanks :smile:


does the Q say whether the volumes of the cone and sphere are equal?

Also, y = 27 is not expressing y in terms of x
If you can't rearrange that then maybe you should get some teaching from proper teachers because it's not the sort of thing you would want to learn off the internet, too much chance of getting something wrong.
(2x)2yπ=4π(3x)3 (2x)^2y\pi = 4\pi(3x)^3
Multiply out the brackets, i.e. (2x)2=22x2=4x2 (2x)^2 = 2^2x^2 = 4x^2 and (3x)3=33x3=27x3 (3x)^3 = 3^3x^3 = 27x^3
So you have
4x2yπ=4π(27x3) 4x^2y\pi = 4\pi(27x^3)
Pi is on both sides, cancel it out.
4x2y=4(27x3) 4x^2y = 4(27x^3)
Now try to get y on its own.
Ah it's y=27x (typo)
Ah there 2 4's and 2 pi so cancel them out, then you are left with:

x^2y=(27x)^3

I get that part, so what is the final part

:smile:
Oh- is the final part y=27x, since the X^3 - X^2 = x
Reply 14
11245264758697089-=98765432567890-=098745324567890-
Thanks for the "troll" comment you left- it is very helpful (GROW UP) :frown:
Sophie Maywood
Oh- is the final part y=27x, since the X^3 - X^2 = x


it is 27x, but not because x^3 -x^2=x

X^2y=27X^3

is there anything we can cancel from each side?
Yes the x
I can answer you, but do you still need help?