Please can someone show me how they worked out that method. I get the top line of working, that's simple, I become stuck on the 2nd line, how did they get 4pi????
The have equal volume. 3(2x)2yπ=34π(3x)3 Both sides have a common denominator, 3, you can multiply it over, or multiply both sides by 3 as was already said, to cancel it out. (2x)2yπ=4π(3x)3 The rest is rearranging an equation.
Please can someone show me how they worked out that method. I get the top line of working, that's simple, I become stuck on the 2nd line, how did they get 4pi????
Thanks
does the Q say whether the volumes of the cone and sphere are equal?
If you can't rearrange that then maybe you should get some teaching from proper teachers because it's not the sort of thing you would want to learn off the internet, too much chance of getting something wrong. (2x)2yπ=4π(3x)3 Multiply out the brackets, i.e. (2x)2=22x2=4x2 and (3x)3=33x3=27x3 So you have 4x2yπ=4π(27x3) Pi is on both sides, cancel it out. 4x2y=4(27x3) Now try to get y on its own.