AS question helpWatch
I got -286kJmol^-1, the same as the standard enthalpy change of formation of water. Is this right? Because it's the same reaction right?
b) What is the standard enthalpy change for the following reaction?
h2O (l) -----> H2(g) + 1/2O2(g)
I put 286kJmol-1 for this one, as is it not the reverse of the formation of water, and so it follows that the enthalpy change will have the reverse sign?
Anyone that could tell me if i'm right or not on these questions would be a great help!
omdz how did u work that out?,......im not sayin itz wrong or right but im jus confused on how u worked it out....i took chem too and enthalpy changes is probz my worst unit of all.......any help on the calculations would be veryyyyy helpful indeed!
PS please don't use text speak on the forum