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A 10 μF capacitor stores 4.5 mJ of energy.

It then discharges through a 25 Ω resistor.

What is the maximum current during the discharge of the capacitor?

A 1.2 A

B 18 A

C 30 A

D 36 A

It then discharges through a 25 Ω resistor.

What is the maximum current during the discharge of the capacitor?

A 1.2 A

B 18 A

C 30 A

D 36 A

Original post by ArifHussain2004

A 10 μF capacitor stores 4.5 mJ of energy.

It then discharges through a 25 Ω resistor.

What is the maximum current during the discharge of the capacitor?

A 1.2 A

B 18 A

C 30 A

D 36 A

It then discharges through a 25 Ω resistor.

What is the maximum current during the discharge of the capacitor?

A 1.2 A

B 18 A

C 30 A

D 36 A

Start with an expression for stored energy, solve to give you a voltage. That is the max voltage at the start of the discharge, so sub that into ohm's law to get a corresponding max current.

can u show me how to do it please?

Original post by Mr Wednesday

Start with an expression for stored energy, solve to give you a voltage. That is the max voltage at the start of the discharge, so sub that into ohm's law to get a corresponding max current.

Original post by ArifHussain2004

can u show me how to do it please?

TSR is not a "do my homework" machine, I have suggested a possible method, if you want more help, give it a go and set out your workings.

Original post by ArifHussain2004

A 10 μF capacitor stores 4.5 mJ of energy.

It then discharges through a 25 Ω resistor.

What is the maximum current during the discharge of the capacitor?

A 1.2 A

B 18 A

C 30 A

D 36 A

It then discharges through a 25 Ω resistor.

What is the maximum current during the discharge of the capacitor?

A 1.2 A

B 18 A

C 30 A

D 36 A

Original post by ArifHussain2004

can u show me how to do it please?

I would recommend that you go through the following materials:

https://www.ibphysicstutor.net/induction_hl#13

More details note in the google slide

https://www.iitianacademy.com/ib-physics-unit-11-electromagnetic-induction-capacitance/

You can check the answer using the following link:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capdis.html

Original post by Mr Wednesday

TSR is not a "do my homework" machine, I have suggested a possible method, if you want more help, give it a go and set out your workings.

Unnecessarily passive-aggressive response.

Original post by username6199731

Unnecessarily passive-aggressive response.

How much teaching experience do you have, the art is in giving students what they need to make progress, not what they want. Oh, and just handing out answers is against the TSR rules.

Original post by Mr Wednesday

Start with an expression for stored energy, solve to give you a voltage. That is the max voltage at the start of the discharge, so sub that into ohm's law to get a corresponding max current.

Original post by 1234kelly

thank you so much for the solution , I got the answer but I wanted to double check why ohms law can be applied to capacitors because I thought there is no resistance in the capacitor ? or are we saying that the Vmax found for the capacitor is exactly the same value as for the resistor so we are actually applying ohms law to the resistor

Note that there is a resistor connected in series with the capacitor.

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