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    Find the slope of the straight line which passes through the point (-2,0) and is tangential to the graph of y = sqrt x

    - How do I know what point the line lies as a tangent to the curve??

    If this turns out to be really obvious, my excuse is that I'm hungover and tired!
    Thanks =]
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    the general straight line through the point has equation y = m(x +2)
    y = rt x

    so you have a pair of simultaneous equations, for which you want only one solution. obtain the quadratic equation and set m so that the discriminant = 0 (i.e. a single root)
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    (Original post by yusufu)
    the general straight line through the point has equation y = m(x +2)
    y = rt x

    so you have a pair of simultaneous equations, for which you want only one solution. obtain the quadratic equation and set m so that the discriminant = 0 (i.e. a single root)
    Ah oui, thankyou =]
 
 
 
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