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Maths question I am so confused in this question

Cars A and B are travelling in the same direction along a straight road. The time t is in seconds.
At t = 0, car A is at rest. It accelerates at 3 ms-2 for 0t 10 and then travels at a constant speed.
Car B travels at 15 ms-1 for 0 t 30 and then accelerates at 1 ms-2 until it reaches a speed of 25 ms-1, after which it continues at this constant speed.
(a) Draw v-t diagrams for the motion of car A and of car B, where v is the speed
in ms-1 and 0 t 80 . [4]
(b) Show that, in the first 40 seconds, car A travels 400 m further than car B. [4]
(c) Given that car A is 500 m behind car B at t = 0, at what value of t does car A
catch up with car B? [2]
Original post by Shirleybee
Cars A and B are travelling in the same direction along a straight road. The time t is in seconds.
At t = 0, car A is at rest. It accelerates at 3 ms-2 for 0t 10 and then travels at a constant speed.
Car B travels at 15 ms-1 for 0 t 30 and then accelerates at 1 ms-2 until it reaches a speed of 25 ms-1, after which it continues at this constant speed.
(a) Draw v-t diagrams for the motion of car A and of car B, where v is the speed
in ms-1 and 0 t 80 . [4]
(b) Show that, in the first 40 seconds, car A travels 400 m further than car B. [4]
(c) Given that car A is 500 m behind car B at t = 0, at what value of t does car A
catch up with car B? [2]


Please post what you've tried.

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