A housing estate consists of 320 houses: 120 detached and 200 semi-detached. The numbers of children living in these houses are shown in the table.

A house estate is selected at random.

D denotes the event ' one child live in the house '.

R denotes the event 'no children live in the house'.

S denotes the event 'one child lives in the house '.

T denotes the event 'two children live in the house '.

(D' denotes the event 'not D'.)

Find:

(A) P(D);

(B)P(D and R);

(C)P(D union T);

A house estate is selected at random.

D denotes the event ' one child live in the house '.

R denotes the event 'no children live in the house'.

S denotes the event 'one child lives in the house '.

T denotes the event 'two children live in the house '.

(D' denotes the event 'not D'.)

Find:

(A) P(D);

(B)P(D and R);

(C)P(D union T);

(edited 1 year ago)

Original post by Namangawi

A housing estate consists of 320 houses: 120 detached and 200 semi-detached. The numbers of children living in these houses are shown in the table.

A house estate is selected at random.

D denotes the event ' one child live in the house '.

R denotes the event 'no children live in the house'.

S denotes the event 'one child lives in the house '.

T denotes the event 'two children live in the house '.

(D' denotes the event 'not D'.)

Find:

(A) P(D);

(B)P(D and R);

(C)P(D union T);

A house estate is selected at random.

D denotes the event ' one child live in the house '.

R denotes the event 'no children live in the house'.

S denotes the event 'one child lives in the house '.

T denotes the event 'two children live in the house '.

(D' denotes the event 'not D'.)

Find:

(A) P(D);

(B)P(D and R);

(C)P(D union T);

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