more physics: pressureWatch

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#1
A diver at a depth of 30.0 m in the deas sea releases an air bubble of volume 2.00cm3 calculate the volume of the bubble in cm3 when it reaches the suface of the sea assuming the temperature of the air in the bubble remains constant.

Densityt of the water in the dead sea = 1170kgm-3

Atmospheric pressure = 101 kPa

Can someone pelase expolain to me how to do this? my textbook is useless.
0
14 years ago
#2
the pressure (at depth h) = density*h*g

use p1v1 = p2v2
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#3
(Original post by elpaw)
the pressure (at depth h) = density*h*g

use p1v1 = p2v2

i dont know what p1v1 or p2v2 is? :'(
0
14 years ago
#4
PV = nRT?
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#5
(Original post by elpaw)
PV = nRT?

whats R and whats n?
0
14 years ago
#6
they're constants, and so is temperature

p1v1 = nRT1

p2v2 = nRT2

T1 = T2 => p1v1 = p2v2
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14 years ago
#7
At the depth of 30.0m, V1 = 2.00cm3,
P1 = weight/area = p.h = 30.0*1170 Pa = 35.1kPa
P2 = 101kPa.
You have P1.V1 = P2.V2 (temperature is constant)
-> V2 = P1V1/V2
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