C2 question. looking for alternative ways of finding the answer Watch
this was in a C2 paper I did. how would you have solved it?
u2 = u1*1.05
u3 = u2*1.05
So it's geometric series, isn;t it?
u1 = 1000
u2 = 1000 + 1000 x 1.05
u3 = 1000 + 1000 x 1.05 + 1000 x 1.05^2
i cant remember the rest of it though - we did this in a practice paper
you can say this is equal to 1000 times the sum from r=1 to 15 of (1.05^r), the latter is a geometric series which can be found and then multiplied by 1000 to get the final value.
however this wasn't taught to us at college so I was searching for a different method. I double checked using an iterative method on the calculator but I think this was too messy to test someone on becuase no one would write down their method.
The interest is 5% , so u2 = 1000 + 1000x5% = 1000x1.05? Why you got
u2 = 1000 + 1000 x 1.05?
you haven't taken into account the additional £1000 added each successive year.
saosmaoosomsom junk to add charachters, 2 is not enough
other people said they just did some lengthy repetetive calculations
I wonder what the markscheme will say, cos it threw me initially and I spent a long time on it.
markscheme > edexcel.org
we did this in a practise test last thursday. Got the last 2 parts of this question wrong.