# Statistics help....again! rep available tomorrow!Watch

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#1
Hey guys, i have posted two problems as pictures below. If anyone can answer them and provide workings I would be hugely grateful. I am out of rep today but will give it tomorrow to the first person to help. Sorry but I am really lost with this kind of thing!

Thanksssssss!
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14 years ago
#2
ok. I can't make out the scales... too blurred...
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14 years ago
#3
Just substitute the values of x (55 and 35) into the equations of the curve given.
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14 years ago
#4
Put the two values given into the equations on the graph as the X values and fing the corresponding Y.
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14 years ago
#5
155
3.155 i believe
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#6
No it has to be exact (to 3 decimal places)....those pictures are as good as I get.....someone answered a similar question for me earlier - you don't need the scales.
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14 years ago
#7
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#8
Yeah maths is not my thing....I suck!
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14 years ago
#9
(Original post by NikNak)
No it has to be exact (to 3 decimal places)....those pictures are as good as I get.....someone answered a similar question for me earlier - you don't need the scales.
I meant using the exponential equations of the curves plotted, see the answer below.
So you substitute in 55 as x in the 1st question, and 35 as x in the second.

EDIT:

154.806... = 155 (to nearest whole no.)
3.1548... = 3.155 (to 3 d.p.)
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#10
yay! thanks Golden Mavrick your a star! you will get rep first thing tomorrow dude!!
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14 years ago
#11
golden maverick how did you get 155 for the 1st question?

just wondering as im trying to see if i can get it.

thanks
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14 years ago
#12
(Original post by james101)
golden maverick how did you get 155 for the 1st question?

just wondering as im trying to see if i can get it.

thanks
I just checked it:

y = 5.4941 x e (0.0607 x 55)
y = 154.806...
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14 years ago
#13
(Original post by NikNak)
Hey guys, i have posted two problems as pictures below. If anyone can answer them and provide workings I would be hugely grateful. I am out of rep today but will give it tomorrow to the first person to help. Sorry but I am really lost with this kind of thing!

Thanksssssss!

1)

y = 5.4941 * e^(0.0607 * x)
We are given that x = 55.

So y= 5.4941 * e^(3.3385)
y=5.4941 * 28.17682975

So y = 154.7189721

y = 155 (0dp)

2)

y= 0.3105 * (x^0.6521)

We are given that x = 35

So y = 0.3105 * (35^0.6521)
=> y = 0.3105 * 10.15983773

So y = 3.154629616

y = 3.155 (3dp)
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14 years ago
#14
You've only got to replace the Xs with the numbers given, NikNak. Maths isn't that scary!
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