This discussion is closed.
john !!
Badges: 14
Rep:
?
#1
Report Thread starter 14 years ago
#1
prove that the difference between the product of all cubes upto that of natural number n and the product of all integers upto n is a multiple of three.
0
Jonny W
Badges: 8
Rep:
?
#2
Report 14 years ago
#2
(n!)^3 - n! = n!((n!)^2 - 1) = n!(n! - 1)(n! + 1) is a product of three consecutive integers and hence is divisible by 3.
0
john !!
Badges: 14
Rep:
?
#3
Report Thread starter 14 years ago
#3
nice work.
takes a lot longer to makea problem than solve it usually !
0
X
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Cardiff Metropolitan University
    Undergraduate Open Day - Llandaff Campus Undergraduate
    Sat, 19 Oct '19
  • Coventry University
    Undergraduate Open Day Undergraduate
    Sat, 19 Oct '19
  • University of Birmingham
    Undergraduate Open Day Undergraduate
    Sat, 19 Oct '19

Why wouldn't you turn to teachers if you were being bullied?

They might tell my parents (23)
6.74%
They might tell the bully (33)
9.68%
I don't think they'd understand (52)
15.25%
It might lead to more bullying (131)
38.42%
There's nothing they could do (102)
29.91%

Watched Threads

View All