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G_S
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question is: show the arrangement of the bonding electrons in [fe(CN)6]4- using the boxs below, clearly showing the electrons donated by the ligands.

[Ar] 3d _ _ _ _ _ _ 4s _ 4p _ _ _

and what is an antidote? how does it function?

thankyou. anyone who helps me will get a rep point!!
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Ben.S.
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(Original post by G_S)
question is: show the arrangement of the bonding electrons in [fe(CN)6]4- using the boxs below, clearly showing the electrons donated by the ligands.

[Ar] 3d _ _ _ _ _ _ 4s _ 4p _ _ _

and what is an antidote? how does it function?

thankyou. anyone who helps me will get a rep point!!
I don't think you can - you've given atomic orbitals for molecular orbital problem! You have to talk about molecular orbital occupancies - however, the Fe (II) will have 6 d electrons in the bonding t2g set (3 MOs, which are essentially the dxy, dxz and dyz atomic orbitals of the metal). The MOs created from the metal 4s and 4p AND the remaining 3d orbitals are occupied by ligand electrons. So, the 6 ligand pairs occupy the 6 lowest lying MOs and the metal valence electrons are accommodated in the higher lying MOs.

Ben
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