Module 4 PHY4 EDEXCEL help Watch
A student was studying the motion of a simple pendulum the time period of which was given by T =2pie x (l/g)sqrooted
He measured T for values of l given by
l/m = 0/1 0/4 0/7 1.0 and plotted a graph of T against sqrRoot L in order to deduce a value of g, the free-fall acceleration.
Explain why these values of l are poorly chosen.
2) A skylab astronauts suggest that the calibration experient with 1kg mass could have been carried out on earth before take off. if a similiar experiment were conducted on earth would the time period be greater, less than, or equal to 1.22 s. Explain your answer.
[period of oscillation outside the earth of the mouse is 1.22 s]
I think this might be to do with the fact that the square roots of 0.1, 0.4 and 0.7 are not very easy values to plot on a graph.
Also, four results might not be enough for an accurate reading.
I add the accuracy bit. All i put before is that if one/two values are outliers then the estimate of g will be serverly affected. [1 mark]
[physics homework_due in monday]
I may go for;
The period doesn't change because of g does not feature in the equation. Therefore, g has no effect.
But the question is for 3 marks.
where k and 2pi are constants and the mass would be the same then the period is the same