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Original post by Sbaiahbe

Exactly what I got, and so the line of reflection was x=2 ?

How did u get 4 coordinates? I only got the second 2

Original post by shasnan

it said c has to be positive. i think the answer is 1

Original post by mtahir05

How did u get 4 coordinates? I only got the second 2

There were 4 stationary points. After finding dy/dx in terms of theta, and setting dy/dx to 0, you end up with four values of theta (because range of graph was 0<theta<2pi), each of which gives a value for x/y when subbing back into the original parametric equations.

(edited 1 month ago)

comprehension bit was horrible. so much yap

Original post by Sbaiahbe

There were 4 stationary points. After finding dy/dx in terms of theta, and setting dy/dx to 0, you end up with four values of theta (because range of graph was 0<theta<2pi), each of which gives a value for x/y when subbing back into the original parametric equations.

damn i only got 2 values of theta, where were the 2 others?

Original post by d4d5

Does any1 know exactly what equation they got for the integration by substitution part with the x+1 = u one

Original post by shr123123413

comprehension bit was horrible. so much yap

It was certainly harder than usual, too few marks for the time some of them took, especially as it wasn’t clear how far you have to go with proving stuff

Original post by Sbaiahbe

Did anyone else get -73/2 for c on the very last question (comprehension)?

Yh I got that.

Original post by MWz

Yh I got that.

y= 6x^2 +smthn x - 73/2

Original post by shkshjsdh

damn i only got 2 values of theta, where were the 2 others?

I'm pretty sure this is the curve, the stationary points are indicated. x=sin(2t)+2, y=2cos(t)+cos(2t)

Original post by WillShill

how many marks did u guys think you got /15 in the comp, cuz i got like 3/4 max

Original post by WillShill

how many marks did u guys think you got /15 in the comp, cuz i got like 3/4 max

I reckon 12 - I had 50 minutes left though to do it and didn't get anything up until 30 minutes left. Kept getting mixed up with the normal maths and the new maths I had got given so I spent ages on it, but it was Ok once I picked out the bits necessary

Original post by WillShill

how many marks did u guys think you got /15 in the comp, cuz i got like 3/4 max

Original post by user_29

What do u guys think an A* will be - lower than last year?

last yrs pure and comp was way easier than this yr

and Pure and mech last yr was a bit easier than this yr

Original post by tom2294

Can someone please say how to do the newton Raphson method question.

Use f(x) = 1/x - cos(x) and starting value of 5, because that's where the gradient function of the original graph looked close to 1 for the first time (positively).

Original post by Sbaiahbe

Use f(x) = 1/x - cos(x) and starting value of 5, because that's where the gradient function of the original graph looked close to 1 for the first time (positively).

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