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AQA A-level Physics Paper 2 (7408/2) - 6th June 2024 [Exam Chat]

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Reply 80

Original post
by man2drippy
Is it because the switch has closed, so the magnetic field through Q is starting to decrease, so to oppose this change the current now flows through the other way?
I'm sorry I'm really bad at explaining, pis Imk if I need to clarify anything

thanks!

Reply 81

Original post
by Barney_W
Im confident theres gonna be 2 big magnetism questions tomorrow and i imagine a fair bit of nuclear physics

zero magnetic fields big questions in the last two years👀 surely right..

Reply 82

is just the symbol for flux linkage or do you actually multiply N by Φ, because then wouldn't the N's on both sides of the equation just cancel out?

Reply 83

Original post
by 888ella
is just the symbol for flux linkage or do you actually multiply N by Φ, because then wouldn't the N's on both sides of the equation just cancel out?

nah that's the symbol otherwise the the equation would just become the formula for flux and not flux linkage

Reply 84

Original post
by SidDaKid_1906
nah that's the symbol otherwise the the equation would just become the formula for flux and not flux linkage

thank you!

Reply 85

Do we have to remember nuclear density equation? if so what is it

Reply 86

Original post
by yoyoalevelsnthat
zero magnetic fields big questions in the last two years👀 surely right..

tbf id quite like magnetic fields questions

Reply 87

for change in potential energy e.g GMm/r1 - GMm/r2 is r1 always the final distance the mass is at?

Reply 88

guys how do I find resultant electric potential. PLS HELP!!

Reply 89

Original post
by gin_n_tonic
Do we have to remember nuclear density equation? if so what is it

yup you do its p = u/(4/3 x pi x (R0)^1/3) where u is the atomic mass unit given in the data sheet, you would also need to know its derivation which should be in the pmt notes

Reply 90

Original post
by SZ.055
guys how do I find resultant electric potential. PLS HELP!!
V = (1/4pi x epsilon not) x Q/r

Reply 91

Original post
by SidDaKid_1906
V = (1/4pi x epsilon not) x Q/r

na bro, u know when you got like 2 charges on a line, and they ask the resultant potential?

Reply 92

Original post
by 888ella
for change in potential energy e.g GMm/r1 - GMm/r2 is r1 always the final distance the mass is at?


No r1 is initial distance
The reason why it’s GMm/r1 - GMm-/r2 is because equation for GPE is -GMm/r and to find change you do final my initial
So that would be -GMm/r2- (-GMm/r1) which is equal to GMm/r1 - GMm/r2

Reply 93

Original post
by SZ.055
na bro, u know when you got like 2 charges on a line, and they ask the resultant potential?


Electric potential is scalar. So you just add them up (I’m pretty sure correct me if I’m wrong)

Reply 94

Original post
by SZ.055
na bro, u know when you got like 2 charges on a line, and they ask the resultant potential?

Just add them up cause they're not vectors so there's no negative sign involved

edit: if two charges are opposite then you'll have to subtract one of them from the other.
(edited 1 year ago)

Reply 95

Original post
by man2drippy
Electric potential is scalar. So you just add them up (I’m pretty sure correct me if I’m wrong)

ok so say u got a positive potential and a negative one yh, u just add the positive number and negative number?

Reply 96

Original post
by SidDaKid_1906
Just add them up cause they're not vectors so there's no negative sign involved
edit: if two charges are opposite then you'll have to subtract one of them from the other.

so -V1+(-V2)?

Reply 97

Original post
by SZ.055
ok so say u got a positive potential and a negative one yh, u just add the positive number and negative number?


Yeah, resultant electric potential is the sum of the individual potentials. Again, anyone correct me if I’m wrong

Reply 98

Original post
by SZ.055
so -V1+(-V2)?

yup, do you have the specific question with you?

Reply 99

Original post
by SZ.055
so -V1+(-V2)?

Always add them, it's only the field strength where direction matters. I may be wrong but I don't think so.

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