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Edexcel A Level Further Mathematics Paper 3B (9FM0 3B) - 14th June 2024 [Exam Chat]

Welcome to the exam discussion thread for this exam. Introduce yourself! Let others know what you're aiming for in your exams, what you are struggling with in your revision or anything else.

Wishing you all the best of luck.

General Information

Date/Time: 14th June 2024/ PM

Length: 1hr 30 mins

Resources:

Edexcel A Level Further Mathematics

Welcome to the exam discussion thread for this exam. Introduce yourself! Let others know what you're aiming for in your exams, what you are struggling with in your revision or anything else.

Wishing you all the best of luck.

General Information

Date/Time: 14th June 2024/ PM

Length: 1hr 30 mins

Resources:

Edexcel A Level Further Mathematics

Scroll to see replies

Bumping this

Not stressing for this one, can't imagine stats ever being too hard

Hi all, I've recorded the score distributions and my answers to each questions. Please tag me if you notice any issues!

1. (6 marks total)

a. (3 marks) Var(X)=4.9

b. (3 marks) Var(X^2)=97.69

2. (7 marks total)

ai. P(X=3) = 0.2090

aii. P(X<2)=0.3084 (2 marks total)

b. (4 marks) The Critical region is A<=1 or A>=12

c. (1 mark) P(Type I)=0.03744

3. (6 marks total)

a. (1 mark) Hypotheses - H0 colour and year group not associated, H1 colour and year group are associated

bi. Black Y10-12 because they are respectively the least frequent favourite colour and year group

ii. 5.383 (2 marks total)

c. (3 marks) (5-1)(3-1)=8 degrees of freedom with critical value 20.090, so reject H0 and conclude there is association between year group and favourite colour

4. (12 marks total)

a. (1 mark) X~Geo(1/6)

b. (2 marks) Show P(X<=3)=91/216

c. (5 marks) E[x]=6, Var(X)=30 -> Var(Xmean)30/64, P(5.6<Xmean<7.2)=0.6806

d. (4 marks) P(X>=16)=test value=0.064905...>0.05 so dont reject H0

5. (10 marks total)

a. (1 mark) H0 p=0.03 and H1 p>0.03

b. (2 marks) Size of test a 0.1821

c. (3 marks) Size of test b 0.2083

di. Power of a 0.7232

ii. We expect 94.877 compontents tested with test b (3 marks total)

e. Use test A as it has lower size and higher power (1 mark)

6. (16 marks total)

a. (6 marks) Variance 6

b. (4 marks) P(X<=2)=203/256

c. (4 marks) Y is a geometric distribution

d. (2 marks) P(X1+X2>5)=729/4096

7. (18 marks total)

a. (2 marks) Sam has prob 0.5886 of winning >=4 times

b. (4 marks) Don't remember what it asked but the answer was 0.04364 apparently

c. (6 marks) Show sam expects to win 1/25(n^2-16n). Sketch - basically set W~B(n, 1/5), then expected winnings is E[w^2+w-n] by sum rule. Then use E[w^2]=Var(W)+E^2[w]=4n/25+n^2/25 and simplify.

d. (4 marks) Sam has probability 0.3518 of not losing money

e. (4 marks) The other person has expected profit r^2-4r

RE predictions: with many people struggling on question 7, I think grade boundaries will be ~55 for A*.

1. (6 marks total)

a. (3 marks) Var(X)=4.9

b. (3 marks) Var(X^2)=97.69

2. (7 marks total)

ai. P(X=3) = 0.2090

aii. P(X<2)=0.3084 (2 marks total)

b. (4 marks) The Critical region is A<=1 or A>=12

c. (1 mark) P(Type I)=0.03744

3. (6 marks total)

a. (1 mark) Hypotheses - H0 colour and year group not associated, H1 colour and year group are associated

bi. Black Y10-12 because they are respectively the least frequent favourite colour and year group

ii. 5.383 (2 marks total)

c. (3 marks) (5-1)(3-1)=8 degrees of freedom with critical value 20.090, so reject H0 and conclude there is association between year group and favourite colour

4. (12 marks total)

a. (1 mark) X~Geo(1/6)

b. (2 marks) Show P(X<=3)=91/216

c. (5 marks) E[x]=6, Var(X)=30 -> Var(Xmean)30/64, P(5.6<Xmean<7.2)=0.6806

d. (4 marks) P(X>=16)=test value=0.064905...>0.05 so dont reject H0

5. (10 marks total)

a. (1 mark) H0 p=0.03 and H1 p>0.03

b. (2 marks) Size of test a 0.1821

c. (3 marks) Size of test b 0.2083

di. Power of a 0.7232

ii. We expect 94.877 compontents tested with test b (3 marks total)

e. Use test A as it has lower size and higher power (1 mark)

6. (16 marks total)

a. (6 marks) Variance 6

b. (4 marks) P(X<=2)=203/256

c. (4 marks) Y is a geometric distribution

d. (2 marks) P(X1+X2>5)=729/4096

7. (18 marks total)

a. (2 marks) Sam has prob 0.5886 of winning >=4 times

b. (4 marks) Don't remember what it asked but the answer was 0.04364 apparently

c. (6 marks) Show sam expects to win 1/25(n^2-16n). Sketch - basically set W~B(n, 1/5), then expected winnings is E[w^2+w-n] by sum rule. Then use E[w^2]=Var(W)+E^2[w]=4n/25+n^2/25 and simplify.

d. (4 marks) Sam has probability 0.3518 of not losing money

e. (4 marks) The other person has expected profit r^2-4r

RE predictions: with many people struggling on question 7, I think grade boundaries will be ~55 for A*.

(edited 1 month ago)

How did everyone find it ?

I thought Q1-6 and 7a and 7b were relatively easy.

But 7c 7d and 7e were horrible and I probably lost all 14 marks 😭😭

I thought Q1-6 and 7a and 7b were relatively easy.

But 7c 7d and 7e were horrible and I probably lost all 14 marks 😭😭

Original post by Fractril

That last question was an absolute beast. Other than that I’d say it was a pretty standard stats exam but the fact that many students might not be able to get the last 14 marks will probably make the grade boundaries quite low.

Do you think an A* might be 55/75 which is 73%

Original post by Ggggfbfbthr

Do you think an A* might be 55/75 which is 73%

Original post by Ggggfbfbthr

How did everyone find it ?

I thought Q1-6 and 7a and 7b were relatively easy.

But 7c 7d and 7e were horrible and I probably lost all 14 marks 😭😭

I thought Q1-6 and 7a and 7b were relatively easy.

But 7c 7d and 7e were horrible and I probably lost all 14 marks 😭😭

exact same as me😭

Original post by yh21

Was the cell that you had to choose the one with a frequency of 3

I picked the one with 3 maybe there was a smaller one or another one with cell value 3?

what the hell was that last question.. i knew it was some sort of series but had absolutely no idea how to go from there

Original post by Vicky Midzy

what the hell was that last question.. i knew it was some sort of series but had absolutely no idea how to go from there

I couldn't get the final answer but I think the grade boundaries will be low as not many people would have gotten that question right

If you do mech 1 and stats 1

Do you think 240/300 (80%) is enough for an A*

If not what do you think it would be

Do you think 240/300 (80%) is enough for an A*

If not what do you think it would be

Original post by Ggggfbfbthr

How did everyone find it ?

I thought Q1-6 and 7a and 7b were relatively easy.

But 7c 7d and 7e were horrible and I probably lost all 14 marks 😭😭

I thought Q1-6 and 7a and 7b were relatively easy.

But 7c 7d and 7e were horrible and I probably lost all 14 marks 😭😭

Yeah I felt that too, Q7 was a killer

Original post by Mal41

How did you work out 1b

Var(X²) = E(X⁴) - [E(X²)]²

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