https://www.quora.com/profile/Bravewarrior/p-158771216

Here is the question. I am stuck on part b. Would really appreciate some help!

Here is the question. I am stuck on part b. Would really appreciate some help!

Original post by pigeonwarrior

https://www.quora.com/profile/Bravewarrior/p-158771216

Here is the question. I am stuck on part b. Would really appreciate some help!

Here is the question. I am stuck on part b. Would really appreciate some help!

a must be > 0 so b^2/b-1 must also be above 0. b^2 term is always positive so we dont worry bout that. therefore b-1 > 0 so b>1 so final restriction is 1<b<a .

Well, what do you think?

Original post by roantpp

a must be > 0 so b^2/b-1 must also be above 0. b^2 term is always positive so we dont worry bout that. therefore b-1 > 0 so b>1 so final restriction is 1<b<a .

Thank you so much! 😀

Original post by tonyiptony

Well, what do you think?

I got to the stage where I did b^2/b-1 > 0 but I did b^2>0 which obviously did not get me anywhere. So the only other thing I could do was b-1>0 but I was not sure if this was right, and if so why

Original post by pigeonwarrior

I got to the stage where I did b^2/b-1 > 0 but I did b^2>0 which obviously did not get me anywhere. So the only other thing I could do was b-1>0 but I was not sure if this was right, and if so why

The idea is to check "what values of b would make your calculation (in)valid" at every step.

So read from the very beginning of the question and analyze at every step - including the given!

Also b-1>0 is not quite right, I think.

Original post by tonyiptony

The idea is to check "what values of b would make your calculation (in)valid" at every step.

So read from the very beginning of the question and analyze at every step - including the given!

Also b-1>0 is not quite right, I think.

So read from the very beginning of the question and analyze at every step - including the given!

Also b-1>0 is not quite right, I think.

Thank you, it makes much more sense now! 🙂

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