Original post by Noname60

when doing these types of questions,I always get the value of μ and the value of X bar mixed up, can someone please tell me how to figure out which is which

Original post by Noname60

In a sense it doesnt really matter as youre calculating the difference (two tailed, so sign doesnt matter), but it would be better to say (test whether) the sample mean is a normal random variable with mean equal to the population mean and the variance equal to the population variance/n so

xbar ~ N(mu, sigma^2/n)

so here xbar = 8.95 (the mean of the sample), and the population parameters are mu=9, sigma^2=0.15^2, and n=30

(edited 2 months ago)

Original post by mqb2766

In a sense it doesnt really matter as youre calculating the difference (two tailed, so sign doesnt matter), but it would be better to say (test whether) the sample mean is a normal random variable with mean equal to the population mean and the variance equal to the population variance/n so

xbar ~ N(mu, sigma^2/n)

so here xbar = 8.95 (the mean of the sample), and the population parameters are mu=9, sigma^2=0.15^2, and n=30

xbar ~ N(mu, sigma^2/n)

so here xbar = 8.95 (the mean of the sample), and the population parameters are mu=9, sigma^2=0.15^2, and n=30

oh thank you very much for your help, I get it now🙂

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