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john !!
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#1
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There is a barber that works in Seville. He shaves everyone who does not shave themselves.

does he shave himself?
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saiyamanadingdongbanana
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(Original post by mik1w)
There is a barber that works in Seville. He shaves everyone who does not shave themselves.

does he shave himself?
no, another barber shaves him :confused:
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john !!
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haha. there are no other barbers!

does he grow a beard ?
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saiyamanadingdongbanana
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(Original post by mik1w)
haha. there are no other barbers!

does he grow a beard ?

Does sandpapering your face constitute as shaving??
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ali_bongo_uk
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i heard he waxes
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Makavelli_07
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(Original post by mik1w)
There is a barber that works in Seville. He shaves everyone who does not shave themselves.

does he shave himself?
Yes.
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Tyler Durden
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(Original post by mik1w)
There is a barber that works in Seville. He shaves everyone who does not shave themselves.

does he shave himself?
He gets permanent laser hair removal.
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ladyshort4u
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S is the set of all sets that do not include themselves.

Now does the barber shave himself or not? Is S a member of S or not? Unless one sneakily attempts to escape the logical trap by positing that the barber is a woman, a machine, or an alien, either answer leads to a contradiction. The existence of such contradictions introduces an uncertainty into mathematical logic itself, not just into the correctness of part of its consensus. That this uncertainty could not in any way be resolved was shown in 1931 by Kurt Gödel when he showed that no set of axioms used to describe a mathematical system could prove both the consistency and completeness of the system.


(lol found this on the following site)
http://www.arjay.ca/EthTech/Text/Ch2/Ch2.2.html
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john !!
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A set S contains all sets which do not contain themselves. Does S contain itself?


how about.

"I am a liar". Am I a liar?
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kikzen
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yes, just for the time being youre telling the truth.
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