# hyperbolic function differentiation help!!!Watch

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#1
How do i split up the fraction -(2sinh2x)/((cosh2x)^2)??? I cant seem to get it to work!
0
14 years ago
#2
(Original post by jmzcherry)
How do i split up the fraction -(2sinh2x)/((cosh2x)^2)??? I cant seem to get it to work!
What do you want to do with it? You mention differentiation - in which case why do you need to split it up further?
0
#3
Its easy enough to see that -2sinh2x/(cosh2x)^2 can be split to -2sech2xtanhx but is there a method you can use to deduce this?
0
14 years ago
#4
I still don't see your problem. The two are easily seen to be identical as you can divide one of the coshs into the sinh to get a tanh, and 1/cosh gives you the sech
0
14 years ago
#5
if you differentiate y = -2sech2x.tanh2x
you get dy/dx = 2[cosh(4x)-3]sech³(2x)
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