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AS1 chemistry question

I’m really stuck on this ccea past paper question from 2017. If anyone has a second some help would be great ty.
Which of the following would exactly neautralise 10.0cm^3 of 1.00mol dm^-3 of NaOH(aq)?
A) 2.50cm^3 of 1.00 mol dm^3 CH3COOH
B) 5.00cm^3 of 1.00 mol dm^3 HCl
C) 5.00cm^3 of 1.00 mol dm^3 H2SO4
D) 3.00cm^3 of 1.00 mol dm^3 H3PO4
Reply 1
Hey there.
The NaOH would give 0.01 x 1 = 0.01 moles of OH-, which all needs to be neutralised. So you would need 0.01 moles of H+. Which acid would give 0.01 moles of H+?



hint

(edited 7 months ago)
Reply 2
Original post by Methene
Hey there.
The NaOH would give 0.01 x 1 = 0.01 moles of OH-, which all needs to be neutralised. So you would need 0.01 moles of H+. Which acid would give 0.01 moles of H+?

hint


Hi! do you multiply the concentration by the volume for each acid? and did u have to figure out if it was a 1:1 ratio of moles?
Reply 3
Original post by user374
Hi! do you multiply the concentration by the volume for each acid? and did u have to figure out if it was a 1:1 ratio of moles?

omg wait is it C because 0.005 times 1 is 0.005 moles and there’s 2 H in H2SO4 so 2 times 0.005 is 0.01
Reply 4
Original post by user374
omg wait is it C because 0.005 times 1 is 0.005 moles and there’s 2 H in H2SO4 so 2 times 0.005 is 0.01

Yep you're right. H+ + OH- -> H2O for 1:1 ratio. n=cv for finding moles

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