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Need help with issac physics Essential Pre-Uni Physics C4a.9 part C only

Not sure how to find the power in these resistors, I find the voltage to be (7/62)V and the resistance to be (1/1 + 1/1)^-1 = 1/2 so:
P = (V^2)/R so: (((7/62)V)^2 )/0.5R but it is wrong. Any help is appreciated
Using your answer to part A (28/31V), the voltage across the parallel combination of three (R, R, 3R) must be 1 - 28/31 = 3/31V. The voltage across the parallel combination of three is the same as for one R resistor, so power can be found using V^2/R.
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(edited 2 months ago)
Reply 2
what would we take R to be?
3/7 does not work, 93/52 does not work, and nor does just R, but yes i am also getting 3/31V for the voltage

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