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SQA Higher maths Paper 2 2024

I think the second last question was
Solve 2sinx - sin^2x = 0, solve for x
Was anyone able to solve this?
Reply 1
Sorry. I meant
2sin2x - (sinx)^2 =0
Reply 2
Original post by Colenso
Sorry. I meant
2sin2x - (sinx)^2 =0

If you post your thoughts on this, someone can check your logic / solutions :smile:

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