If you used Clearing in 2024, how did you find it?

AQA AS Maths Paper 1 [16th May 2024] Discussion

Frokeii

How did you guys find it?

Reply 1

Stash123

Many people seem to have liked it

Reply 2

Bobbio

Original post by Frokeii

How did you guys find it?

Forgot the cosine rule :frown:

Reply 3

Frokeii

Original post by Bobbio

Forgot the cosine rule :frown:

I accidently multiplied by the angle itself instead of the sin for the sheep question😭 so I'm cooked

mechanics section was good though

Reply 4

Bobbio

Original post by Frokeii

I accidently multiplied by the angle itself instead of the sin for the sheep question😭 so I'm cooked
mechanics section was good though

For the last question in mechanics I actually didn`t know what to do. Like I can see where the 1/11g can come from but I couldn`t find an answer. Tried like F=ma. W=mg, suvat and nothing worked. Would`ve been such a nice paper without this question though

Reply 5

Frokeii

Original post by Bobbio

what was the question again ? i can't remember

Reply 6

Bobbio

Original post by Frokeii

what was the question again ? i can't remember

Question 19. Pulley with 2 weights, one is 0.6kg another 0.5kg. Show that a=1/11 times g. Smth like that

Reply 7

Frokeii

Original post by Bobbio

Question 19. Pulley with 2 weights, one is 0.6kg another 0.5kg. Show that a=1/11 times g. Smth like that

ohhh okay, I'll explain it

so you know that N had mass of 0.5kg and M had mass 0.6kg, and they were attached by a light, inextensable rope. It told you that they moved with acceleration, a, when they were let go from rest, and since M had a greater mass of 0.6kg, that one would move down meaning N moves up.
This let's you form 2 equations of F = ma.
Since the string is light and inextensable, the tension is constant throughout meaning both masses experience the same tension

So Since M moved down, (resultant force works with weight), it's equation Is 0.6g - T = 0.6a
Since M moved up (weight is opposing it), then it's equation is T -0.5g = 0.5a

You add these together to cancel out tension, getting you 0.1g = 1.1a. Divide by 1.1 so you get a on it's own, 0.1g/1.1 = 1g/11

Reply 8

Bobbio

Original post by Frokeii

ohhh okay, I'll explain it
so you know that N had mass of 0.5kg and M had mass 0.6kg, and they were attached by a light, inextensable rope. It told you that they moved with acceleration, a, when they were let go from rest, and since M had a greater mass of 0.6kg, that one would move down meaning N moves up.
This let's you form 2 equations of F = ma.
Since the string is light and inextensable, the tension is constant throughout meaning both masses experience the same tension
So Since M moved down, (resultant force works with weight), it's equation Is 0.6g - T = 0.6a
Since M moved up (weight is opposing it), then it's equation is T -0.5g = 0.5a
You add these together to cancel out tension, getting you 0.1g = 1.1a. Divide by 1.1 so you get a on it's own, 0.1g/1.1 = 1g/11

Thank you,that is very helpful. I have lost some marks on this but I hope I will come back better at paper 2.

Reply 9

olygilly

Original post by Frokeii

How did you guys find it?

I found really hard

Reply 10

Frokeii

Original post by olygilly

I found really hard

don't worry bro there's always paper 2

Reply 11

olygilly

Original post by Frokeii

don't worry bro there's always paper 2

My strenght was pure lol

Reply 12

Frokeii

https://vm.tiktok.com/ZGeX8yDqu/

this guy went through the paper

Reply 13

olygilly

Original post by Frokeii

https://vm.tiktok.com/ZGeX8yDqu/
this guy went through the paper

That is maths. I took pure maths but thank you

Reply 14

cbush6016

Original post by Frokeii

How did you guys find it?

Had it for my "yr 12 mocks" I think it was a decent paper. The mechanics was my strength, some of the pure was a bit obnoxious. But overall a decent paper