i need help im stuck on this question
When solid lead(II) sulfate is added to aqueous sodium iodide, an equilibrium
is established.
PbSO4(s) + 2I
–
(aq) PbI2(s) + SO4
2–(aq)
The expression for the equilibrium constant, Kc , for this reaction is
Kc =
[SO (aq)]
[ (aq)]2
4
2−
−
I
In an experiment, Kc may be determined by adding excess lead(II) sulfate to
25.0cm3
of 0.100moldm–3 sodium iodide.
The volume remains constant at 25.0cm3
.
The mixture is left to reach equilibrium at room temperature.
Ice-cold water is added to freeze the position of equilibrium and the mixture is
then titrated with standard silver nitrate solution.
The whole mixture requires 12.20cm3
of 0.0500moldm–3 silver nitrate solution to
react with the aqueous iodide ions at equilibrium.
Ag+
(aq) + I–
(aq) → AgI(s)
Calculate the equilibrium concentrations of the sulfate ions and the iodide ions,
and hence the value of Kc at room temperature.
Give your answer to an appropriate number of significant figures and include
units for Kc , if any.
i have got to the step where you divide the value by 2 to make it equal.
but after that the mark scheme divides each value separately by 25 and multiplies by a thousand i have no clue why...
its the 2022 paper 1 edexcel the very last question