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footballhead
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#1
Triangle ADE
Where AD is the hypotenus and is x metres
And angle AED is a rightangle
ADE IS also isoscles

show that the area of the triangle ADE is 1/4x^2 m2
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evariste
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(Original post by LondonBoy)
Triangle ADE
Where AD is the hypotenus and is x metres
And angle AED is a rightangle
ADE IS also isoscles

show that the area of the triangle ADE is 1/4x^2 m2
AD=x
AED right angle by pythag
AED isos so AE=ED (1) and hence AE^2=ED^2 (2)
AD^2=AE^2+ED^2
AD^2=2AE^2...................usi ng(2)
x^2/2=AE^2.
area=1/2(AE.ED)
=1/2(AE)^2.....................usin g(1)
=1/2(x^2/2)=x^2/4
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