Edexcel AS Statistics and Mechanics 2024

How was it for u guys icl mechanics was really good

Reply 1

ektez

2

What topics came up

Reply 2

Original post by omarrryf

How was it for u guys icl mechanics was really good

I think the stats was good. Can someone explain how to do the vectors question? Mass 2kg, force 2i + 4j force ci - 2j and acceleration root 5? I spent all my remaining time on it and got nowhere ☹️ I hate vectors

Reply 3

TutorEmil

DId you try applying F=ma to direction i and j seperately?

Reply 4

Original post by TutorEmil

DId you try applying F=ma to direction i and j seperately?

I tried but didnt get anywhere. The forces down was 2gN and 2N and the force upwards was 4N so the force down was greater than the force upwards.
Then horizontally I could get three values of C, c being negative but accelerating to the left, c being negative but accelerating to the right or c being positive and acceleration right. I just dont get it at all ☹️

Reply 5

TutorEmil

can you send me the whole question, perhaps I can provide you with the full answer then,

Reply 6

Original post by TutorEmil

can you send me the whole question, perhaps I can provide you with the full answer then,

I cant remember the exact wording but it was something like...
A object of mass 2kg is moving along a horizontal surface. It is acted on by two forces (2i +4j)N and (ci - 2j)N. The magnitude of the acceleration is root 5. Work out the two possible values of c.

Reply 7

giggia

Original post by Vvgsisb

I think the stats was good. Can someone explain how to do the vectors question? Mass 2kg, force 2i + 4j force ci - 2j and acceleration root 5? I spent all my remaining time on it and got nowhere ☹️ I hate vectors

What were the stats questions?

Reply 8

omarrryf

OP

Original post by Vvgsisb

I think the stats was good. Can someone explain how to do the vectors question? Mass 2kg, force 2i + 4j force ci - 2j and acceleration root 5? I spent all my remaining time on it and got nowhere ☹️ I hate vectors

Multiply the 2 to the root 5 cuz f=ma then u set up ur position vectors it was (2) + (c) which is 2i+ci+2j
( 4) + (-2)
Then u do the magnitude formula so the square root of (2+c)^2 + (2)^2 =2root 5 get rid of square root by squaring both sides so solving c^2 +4c + 4 + 4 = 20 and then itll be c^2 + 4c - 12 = 0 solving them both you get (c+6)(c-2) therefore c= -6 and c= 2

Reply 9

TutorEmil

Sum of forces are (2+c)i+2j
apply F=ma
|F|=m|a|
therefore, sqrt((2+c)^2+2^2)=2*sqrt(5)
Can you continue now?
PS: you dont need to consider gravity force since its on ground

Reply 10

Sirgalackir

Original post by omarrryf

How was it for u guys icl mechanics was really good

I finished that exam. I got full in mechanics and 24/30 in stats. Makes up for my 80/100 in the pure. That was a horrendous exam

Reply 11

Sirgalackir

Original post by TutorEmil

Sum of forces are (2+c)i+2j
apply F=ma
|F|=m|a|
therefore, sqrt((2+c)^2+2^2)=2*sqrt(5)
Can you continue now?
PS: you dont need to consider gravity force since its on ground

That question was so light!!!

Reply 12

giggia

What did you get for K in the histogram?
Also for the hypothesis test did you accept it reject the H0?

Reply 13

kjdlsafj

Do any of you have the full paper or full questions? I wanna go back thru it

Reply 14

Yunustheboss

Original post by giggia

What did you get for K in the histogram?
Also for the hypothesis test did you accept it reject the H0?

K was 128, you had to integrate and you know the area is 112 as freq density times class width is frequency.
I DID NOT reject h0, I don't think you can accept as in some mark schemes it says do not allow accept

Reply 15

giggia

Original post by Yunustheboss

K was 128, you had to integrate and you know the area is 112 as freq density times class width is frequency.
I DID NOT reject h0, I don't think you can accept as in some mark schemes it says do not allow accept

Yes right insufficient evidence to ….

Reply 16

Yunustheboss

All I remember for the last q for stats was 0.8

Reply 17

kjdlsafj

What was the Large Data Set question?

Reply 18