The Student Room Group

AS OCR MEI B Further Maths Modelling With Algorithms

Guaranteed nobody does this but if any other soul does

HOW WAS IT? I FOUND THAT SO GOOD
Reply 1
I did it! Found it ok on the whole, what were your answers for the 10 marker at the end? I got x=22, y= 50, z=55, £850
Much better than pure anyway 💀
Reply 2
wait i got 23 50 57 ! will there be like some leniency???
Reply 3
Original post by rohin1
wait i got 23 50 57 ! will there be like some leniency???
Yeah I imagine so, it’s probably based on ur graph so there would be some leniency
Reply 4
Original post by edgbarrow
I did it! Found it ok on the whole, what were your answers for the 10 marker at the end? I got x=22, y= 50, z=55, £850
Much better than pure anyway 💀


i got x= 14, y= 50 and z= 36, then the reason why he might not be able to use the optimal solution is because it exceeds the time limit of less than or equal to 100 hours
Reply 5
Original post by oljo888
i got x= 14, y= 50 and z= 36, then the reason why he might not be able to use the optimal solution is because it exceeds the time limit of less than or equal to 100 hours
Was x and z not in the ratio 2:5??
Reply 6
Original post by edgbarrow
Was x and z not in the ratio 2:5??


yeah it was, i put 5x = 2z meaning z = 5/2x

if you substitute x = 2 into that, you get z = 5, which puts x and z in the ratio 2:5

i think most people put z = 2/5x, from what i’ve heard at least. but substituting x = 2 gives z = 4/5, which a) is not in the ratio of 2:5 and b) you can’t have a fraction of a shirt.
Reply 7
Original post by oljo888
yeah it was, i put 5x = 2z meaning z = 5/2x
if you substitute x = 2 into that, you get z = 5, which puts x and z in the ratio 2:5
i think most people put z = 2/5x, from what i’ve heard at least. but substituting x = 2 gives z = 4/5, which a) is not in the ratio of 2:5 and b) you can’t have a fraction of a shirt.

Yeah lots of people from my school did that too

Quick Reply