The Student Room Group

A level parametric integration question

idk how to integrate the equation for part a (ii)

https://imgur.com/a/SH8c9t1
You could note that 60sin(t) is a multiple of the derivative of cos(t). This should suggest an integration method.
Reply 2
Original post by old_engineer
You could note that 60sin(t) is a multiple of the derivative of cos(t). This should suggest an integration method.

i tried doing by inspection
i chose to inspect 60sint
i raised it by one power so it’s 60sin^2(t)
after i differentiated that i got 120sintcost but i don’t see how u can divide that by anything to get the original formula of 60sintcos^2(t)

https://imgur.com/a/8eCrxqm
Original post by esha06
i tried doing by inspection
i chose to inspect 60sint
i raised it by one power so it’s 60sin^2(t)
after i differentiated that i got 120sintcost but i don’t see how u can divide that by anything to get the original formula of 60sintcos^2(t)
https://imgur.com/a/8eCrxqm

You possibly need to "inspect" the other element of the function to be integrated...
Reply 4
Original post by esha06
i tried doing by inspection
i chose to inspect 60sint
i raised it by one power so it’s 60sin^2(t)
after i differentiated that i got 120sintcost but i don’t see how u can divide that by anything to get the original formula of 60sintcos^2(t)
https://imgur.com/a/8eCrxqm
nvm i realised u have to inspect cos^2(t) instead 🤦🏽*♀️
Original post by esha06
nvm i realised u have to inspect cos^2(t) instead 🤦🏽*♀️

Note you could also use integration by parts, although it is one of those tricky ones where it looks as though you're going round in circles.
Reply 6
Original post by old_engineer
Note you could also use integration by parts, although it is one of those tricky ones where it looks as though you're going round in circles.
i think i should stick to this one considering i could barely do this way properly 😭😭😭
Reply 7
Inspection, substitution and parts all work!

If inspection works substitution also work but with more steps kinda, parts it tedious.

https://imgur.com/a/bikVMEN
Reply 8
Original post by esha06
i think i should stick to this one considering i could barely do this way properly 😭😭😭

u can use the substitution u=cos t and it works out really nicely!

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