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practical skills aqa a level question

Screenshot 2024-06-08 135027.png
This equation is used for a graph of n (x axis) against the square root of (4x^2+y^2) (y axis).

One of the questions asks you to find the value of y using this graph. The mark scheme states that it is the y intercept. The reason that I am confused by this is because y is not a constant value as it is linked to (4x^2 + y^2), so I wouldn't have assumed that to be the y intercept.

Need some help understanding this if possible
√(4x²+y²) = + y
y-intercept is when x = 0, so set n = 0:
√(4x²+y²) = 0 + y = y

It doesn't matter that the left hand side also has y's in it.
The fact is that when x = 0, the y-intercept is always going to be y.
It is a bit confusing but hopefully this helps :smile:
Reply 2
Thank you :smile:

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