(a) Assuming air to be an ideal gas, calculate the number of moles of air left in a scuba diver's tank if it has a volume of

12 litres and, when in 15 C° water, the pressure is 2× 10^7 Pa.

(b) What would be the new rms speed of the molecules in the scuba tank when it is immersed in water so its temperature becomes 12°C?

the answer to the first question is 100.3 mol.

but i cant calculate the answer to the second one..........

12 litres and, when in 15 C° water, the pressure is 2× 10^7 Pa.

(b) What would be the new rms speed of the molecules in the scuba tank when it is immersed in water so its temperature becomes 12°C?

the answer to the first question is 100.3 mol.

but i cant calculate the answer to the second one..........

(edited 1 month ago)

Original post by Silver S

(a) Assuming air to be an ideal gas, calculate the number of moles of air left in a scuba diver's tank if it has a volume of

12 litres and, when in 15 C° water, the pressure is 2× 10^7 Pa.

(b) What would be the new rms speed of the molecules in the scuba tank when it is immersed in water so its temperature becomes 12°C?

the answer to the first question is 100.3 mol.

but i cant calculate the answer to the second one..........

12 litres and, when in 15 C° water, the pressure is 2× 10^7 Pa.

(b) What would be the new rms speed of the molecules in the scuba tank when it is immersed in water so its temperature becomes 12°C?

the answer to the first question is 100.3 mol.

but i cant calculate the answer to the second one..........

You can use

$v_{rms} = \sqrt{\dfrac{3RT}{M}}$

where M is the molar mass in kilograms per mole.

Original post by Eimmanuel

You can use

$v_{rms} = \sqrt{\dfrac{3RT}{M}}$

where M is the molar mass in kilograms per mole.

$v_{rms} = \sqrt{\dfrac{3RT}{M}}$

where M is the molar mass in kilograms per mole.

thank you, i finally got it right

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