I think you would need to find the equation of the inverse function. Use that to determine the x coordinate given y=3 Differentiate it to obtain the gradient function. Calculate the gradient at the x value that corresponds to the y value of 3
Ok that sounds like it would work. Here is the mark scheme method I'm not entirely sure what they've done
Ok that sounds like it would work. Here is the mark scheme method I'm not entirely sure what they've done
Looks like they've worked out h'(3) and then used the fact that the gradient of the inverse function at y = 3 is the reciprocal of the original function at x = 3.