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UCAT quantitative reasoning question

Hi, please could I have help on this question? I don’t understand what it’s asking or how to work it out?
Here is the question: https://app.gemoo.com/share/image-annotation/660926094861414400?codeId=DWLdRbbNXZ1k4&origin=imageurlgenerator

Thank you!!
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Reply 2
Original post by anonymous294
Hi, please could I have help on this question? I don’t understand what it’s asking or how to work it out?
Here is the question: https://app.gemoo.com/share/image-annotation/660926094861414400?codeId=DWLdRbbNXZ1k4&origin=imageurlgenerator
Thank you!!

It is saying the ratio of how fast the boat goes when travelling wiht the current to how fast it goes when travelling against the current is 2:1.
It gets a 3km/h helping hand when with the current and a 3km/h hindrance when against it. They are saying use that to trial the answers and see which one fits
Original post by GANFYD
It is saying the ratio of how fast the boat goes when travelling wiht the current to how fast it goes when travelling against the current is 2:1.
It gets a 3km/h helping hand when with the current and a 3km/h hindrance when against it. They are saying use that to trial the answers and see which one fits
Thank you for your reply, but how do you know that there is a helping hand with the current and hindrance against? Also I don’t get how they work out the speed in neutral water, what does that mean?
Reply 4
Original post by anonymous294
Thank you for your reply, but how do you know that there is a helping hand with the current and hindrance against? Also I don’t get how they work out the speed in neutral water, what does that mean?

The current is pushing against the boat to the tune of 3km/h, ie hindering it, when it travels against the current. It gets pushed along by an extra 3km/h when it is travelling with the current. It tells you the water is moving at 3km/h, so that is how fast the boat would travel without any power (well, it isn't, as if takes no account of other forces, but you are meant to assume it is for this question).
They are asking you to work out how fast the boat would travel when there is no current, either for or against, ie neutral water

You can do it as algebra, if you want
x+3 = 2(x-3)
x+3 = 2x-6
3=x-6
9=x
(edited 3 weeks ago)

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