I got under 1KG so maybe I was wrong. Work out the area of the outer circle minus the inner circle area then multiply by the length, then multiple by the density is what I did

Reply 13

bigfoot123

Original post by HQuilliam

How did you guys work out the current of the circuit for the photoelectric effect?

I = Q/T and you worked out the number of electrons per second from the previous question I think, then multiply it by the charge of an electron to find the rate of flow of charge per second (current).

Reply 14

bigfoot123

For the copper tube, how did everyone find the temperature change of it? I used Q=mc(theta) and used Q = GPE of the mass inside. Idk it’s probably wrong to be honest. Didn’t know what else to do.

Reply 15

Shuyu Lin Angela

Do you think it is harder or easier?

Reply 16

Robbie green

Original post by stfl_nemesis

What did you guys get for the mass of the copper. I got 1.05kg

Yep I got that aswell🔥🔥

Reply 17

Ouegh

Original post by bigfoot123

You can do it by stating that the same number of electrons released by the current in a unit of time is equivalent to the number of photons incident on the plate, so you just completely remove n and t as well.

Reply 18

bigfoot123

Original post by Ouegh

Yeh basically just the number of photons per second multiplied by the charge of one electron I think is what I did.

Reply 19

Ouegh

Original post by bigfoot123

For the copper tube, how did everyone find the temperature change of it? I used Q=mc(theta) and used Q = GPE of the mass inside. Idk it’s probably wrong to be honest. Didn’t know what else to do.

I did that, and just to be safe, stated that due to the terminal velocity being low, there is no change in KE (initially at rest, at the end at rest). Btw, for the light and wave particle question, I said that Double slit showed light difrracts (property of a wave), and also that photoelectric effect and UV catastrophe show it acts as a particle, but at the time, the Thompson's electron diffraction showed that particles can behave as waves under special circumstances, which is why the theory for dual wave - particle behaviour was taken. Would that work? (Also, for the first question, final part, i said wave is longitudinal, so the vertical railings aren't able to polarise them, hence the dude is wrong, they aren't polarised, does that get me full marks?