Reply 1
Reply 3
Bit late, but you do have an alternative approach - spot the wrong answers and use the process of elimination.
A is wrong, because the positioning of the groups in a given molecule affects how much contact the molecules have with each other. Therefore, the london dispersion forces between the molecules for different geometric isomers are not of the same strengths, hence they have different melting and boiling points.
C is problematic, since you are expected to know that the region described is the fingerprint region and each molecule (and incidentally each geometric isomer) has a uniquely shaped pattern in this region.
D is not correct, as molecular ion peaks don’t just have an associated m/z value. You also have to take into account the intensities of the peaks. Since the molecular ions themselves will have near-identical structures to their parent alkenes, you can argue that the respective molecular ions must be different to each other as the groups are locked in place by the C=C bond with limited rotation. This means the molecular ions formed in each case are not the same and therefore not equally stable, so the intensities of the M^+ peaks will not be the same.
A is wrong, because the positioning of the groups in a given molecule affects how much contact the molecules have with each other. Therefore, the london dispersion forces between the molecules for different geometric isomers are not of the same strengths, hence they have different melting and boiling points.
C is problematic, since you are expected to know that the region described is the fingerprint region and each molecule (and incidentally each geometric isomer) has a uniquely shaped pattern in this region.
D is not correct, as molecular ion peaks don’t just have an associated m/z value. You also have to take into account the intensities of the peaks. Since the molecular ions themselves will have near-identical structures to their parent alkenes, you can argue that the respective molecular ions must be different to each other as the groups are locked in place by the C=C bond with limited rotation. This means the molecular ions formed in each case are not the same and therefore not equally stable, so the intensities of the M^+ peaks will not be the same.
(edited 8 months ago)
Quick Reply
Related discussions
- Chemistry OCR Alevel
- SQA Advanced Higher Chemistry - 23rd May 2024 [Exam Chat]
- Chem question help please organic
- Drawing and Naming groups with cis and trans
- Business Paper 2 WJEC
- Aqa psychology
- Helping w aqa gcse french (from a g9 student)
- which statement about (ch3)2chch2cooh is correct
- Riddle
- Helping with gcse french 🙈💕
- chemistry aqa as level isomerism question
- Help with choosing A Levels
- Workload
- idea.org.uk
- Optical isomerism
- iGCSE Edexcel Biology Paper 1BR 2024 marks
- What do you guys think the grade boundaries for OCR a level chemistry will look like?
- Health and Social care or Media Studies???
- Which a level has this which hate
- Bestie is crushing hard
Latest
Trending
Last reply 1 month ago
OCR AS Level Chemistry A Paper 2 - Depth ( 21th May 2024)