Why can't it be all three? Why can't 1 line work.1 line in my diagram literally works. It is a straight line to give 2 triangles. Assume this is an obtuse angle.
It would probably be clearer to draw triangles which are more acute/obtuse, rather than something which is almost right. But assuming the top angle is > 90, then you have drawn the obvious altitude, but you could put two other lines on there that divide the obtuse angle into 90+acute and acute+90 and youd have 3 distinct lines.
It would probably be clearer to draw triangles which are more acute/obtuse, rather than something which is almost right. But assuming the top angle is > 90, then you have drawn the obvious altitude, but you could put two other lines on there that divide the obtuse angle into 90+acute and acute+90 and youd have 3 distinct lines.
But why do I need these 2 other lines? This makes 0 sense. You have 1 line, it makes 2 right angles, which is sufficient for the "1 straight line", why do i HAVE to have 2 other lines?
But why do I need these 2 other lines? This makes 0 sense. You have 1 line, it makes 2 right angles, which is sufficient for the "1 straight line", why do i HAVE to have 2 other lines? What is an altitude? This isn't on the TMUA spec.
The question says exactly one, two or three. The answer is that there are always 3 lines which give at least one right angled triangle. So if there are 3 lines, then if you just draw one of them, it does not mean there are exactly one. There are exactly 3.
So if the triangle is acute, you can draw 3 lines, starting at each vertex and meeting the opposite side at a/two right angle, so each line produces two right triangles. Theyre called altitudes. Its just a name.
If your triangle is obtuse, you can draw one line starting at the obtuse vertex and meeting the opposite side at a/two right angles as before. However, you could also draw two other lines which start at the opposite side and divide the obtuse angle into 90+acute and acute+90, each producing one right triangle. So there are exactly 3 such lines.
i managed to get 1,2 & 3 lines: i) for 1 line use an isosceles triangle ii) for 3 lines use an equilateral triangle iii) for 2 lines use an obtuse triangle
Just as well youre not taking the tmua :-). The answers is always 3 when the original triangle is not right.
The question says exactly one, two or three. The answer is that there are always 3 lines which give at least one right angled triangle. So if there are 3 lines, then if you just draw one of them, it does not mean there are exactly one. There are exactly 3. So if the triangle is acute, you can draw 3 lines, starting at each vertex and meeting the opposite side at a/two right angle, so each line produces two right triangles. Theyre called altitudes. Its just a name. If your triangle is obtuse, you can draw one line starting at the obtuse vertex and meeting the opposite side at a/two right angles as before. However, you could also draw two other lines which start at the opposite side and divide the obtuse angle into 90+acute and acute+90, each producing one right triangle. So there are exactly 3 such lines.
but what is telling us that we need to have the other 2. 1 line works enough to be sufficient. is there anything blocking the requirement of 2 other lines that NEED to be there? I am really confused
but what is telling us that we need to have the other 2. 1 line works enough to be sufficient. is there anything blocking the requirement of 2 other lines that NEED to be there? I am really confused
The question asks for how many lines there are, and there are exactly 3, as described in the previous post.
If you just draw 1, the other 2 still exist. Youve just not drawn them.
The question asks for how many lines there are, and there are exactly 3, as described in the previous post. If you just draw 1, the other 2 still exist. Youve just not drawn them.
I really am confused. I really can't understand why 3 is required or why I need to have the other 2. I'm not wrong for thinking if I drew one line I meet the criteria, but I don't understand why I need to draw 3 lines
I really am confused. I really can't understand why 3 is required or why I need to have the other 2. I'm not wrong for thinking if I drew one line I meet the criteria, but I don't understand why I need to draw 3 lines
Without being funny, do you understand why an acute angled triangle can be divided by 3 lines (altitudes) as in the previous post?
Do you understand why an obtuse triangle can be divided by 1 altitude (the line you drew) and 2 other lines, both of which start at the side opposite the obtuse angle and they split the obtuse angle into a right angle + an acute angle? Again as described in the previous post.
Its not about need or required or ... Each triangle can be divided by 3 such lines.
Without being funny, do you understand why an acute angle can be divided by 3 lines (altitudes) as in the previous post? Do you understand why an obtuse triangle can be divided by 1 altitude (the line you drew) and 2 other lines, both of which start at the side opposite the obtuse angle and they split the obtuse angle into a right angle + an acute angle? Again as described in the previous post. Its not about need or required or ... Each triangle can be divided by 3 such lines.
I understand that 3 lines work. I do not understand why 1 or 2 lines don't work. Why do I have to divide by 3 total lines.
There are exactly 3 such lines. There is not exactly 1 line as there are 3.
ok but you are not explaining to me why there are 3 lines only. Their mark scheme really confuses me because it both contradicts what your saying that obtuse has 1 line yet has 3?
ok but you are not explaining to me why there are 3 lines only. Their mark scheme really confuses me because it both contradicts what your saying that obtuse has 1 line yet has 3?
For every acute or obtuse triangle, there are exactly 3 lines. The construction described in #6 explains how this occurs in each case (acute/obtuse). The obtuse case has 3 lines, one of which is the altitude (which you drew) and the other two start at the side opposite the obtuse vertex and divide the obtuse angle into right+acute angles.
Why not try drawing the acute and obtuse triangle cases and convince yourself that there are always 3 lines as described. Thats why the answer is D (3 lines).