Integrating complex log functions
15
I haven’t been given a specific name for what this rule is called. The course actually refers to it as a trig function lol.
Anyway, see attached based on the information it gives me:
I guess I half understand but not fully because my test question answer is incorrect.
This is their example to work through.
This is my attempt to understand what’s happening but I appear to be wrong.
Anyway, see attached based on the information it gives me:
I guess I half understand but not fully because my test question answer is incorrect.
This is their example to work through.
This is my attempt to understand what’s happening but I appear to be wrong.
(edited 11 months ago)
Reply 1
21
Original post by KingRich
I haven’t been given a specific name for what this rule is called. The course actually refers to it as a trig function lol.
Anyway, see attached based on the information it gives me:
I guess I half understand but not fully because my test question answer is incorrect.
This is their example to work through.
This is my attempt to understand what’s happening but I appear to be wrong.
Anyway, see attached based on the information it gives me:
I guess I half understand but not fully because my test question answer is incorrect.
This is their example to work through.
This is my attempt to understand what’s happening but I appear to be wrong.
Its not multiplied by 2, its multplied by ....
Reply 2
KingRich
OP
15
Original post by mqb2766
Its not multiplied by 2, its multplied by ....
So, here’s why I am confused. I was just introduced the new approach as shown in photos above but It seems that the best approach is to use ∫1/kx+b =1/k In |kx + b|.
Informing me that the answer is In(17)/2…
Right!!! After, trying this approach, I now see my error.
2x³ = 1/2’ f(x) not 2! Ah! Thank you
Reply 3
21
Original post by KingRich
So, here’s why I am confused. I was just introduced the new approach as shown in photos above but It seems that the best approach is to use ∫1/kx+b =1/k In |kx + b|.
Informing me that the answer is In(17)/2…
Right!!! After, trying this approach, I now see my error.
2x³ = 1/2’ f(x) not 2! Ah! Thank you
Informing me that the answer is In(17)/2…
Right!!! After, trying this approach, I now see my error.
2x³ = 1/2’ f(x) not 2! Ah! Thank you
As youd expect, either approach should work, but sometimes just working back from the answer to get to the question is the way. So the derivative of
ln(x^4+1) + c
gives
4x^3 / (x^4+1)
so youd need to multiply by 1/2 to get to 2x^3 on the numerator.
Its also worth noting the usual log property so
a*ln(x) = ln(x^a)
and a question may ask for answer to be in either form, but its not necessary here. So your multipliers of 1/2 or 2 would correspond to sqrt or ^2 of the log argument.
(edited 11 months ago)
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