Help with A LEVEL TRIG
Hello, I'll put the image in the desc... fingers crossed it works!
Reply 1
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Reply 2
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Original post
by mitostudentWhich part? You could almost go directly from the first expression to the last as you should know the basic pythagoean identity
1 + tan^2 = sec^2
Reply 3
12
Original post
by mqb2766Which part? You could almost go directly from the first expression to the last as you should know the basic pythagoean identity
1 + tan^2 = sec^2
1 + tan^2 = sec^2
I've only covered the AS content so haven't heard of that 😭
Reply 4
21
Original post
by mitostudentI've only covered the AS content so haven't heard of that 😭
Its simply
sin^2 + cos^2 = 1
which you have covered and divide by cos^2 so
tan^2 + 1 = 1/cos^2 = sec^2
and the question is simply this but as a reciprocal.
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