Help with A LEVEL TRIG
Hello, I'll put the image in the desc... fingers crossed it works!
Original post by mitostudent
Which part? You could almost go directly from the first expression to the last as you should know the basic pythagoean identity
1 + tan^2 = sec^2
Original post by mqb2766
Which part? You could almost go directly from the first expression to the last as you should know the basic pythagoean identity
1 + tan^2 = sec^2
1 + tan^2 = sec^2
I've only covered the AS content so haven't heard of that 😭
Original post by mitostudent
I've only covered the AS content so haven't heard of that 😭
Its simply
sin^2 + cos^2 = 1
which you have covered and divide by cos^2 so
tan^2 + 1 = 1/cos^2 = sec^2
and the question is simply this but as a reciprocal.
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