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Further math(imaginary numbers question)

Um the question is: Given that (a+3i)(1+bi)=25-39i find two possible pairs of values for a and b. So I attempt the question and I did expand the brackets and then made a simultaneous equation for real and imaginary part but I’m stuck here 1) a+3bi^2=25 2)abi+3i=-39i . I need a suggestion how should I make them into one equation
Reply 1
Original post by zv0_qw
Um the question is: Given that (a+3i)(1+bi)=25-39i find two possible pairs of values for a and b. So I attempt the question and I did expand the brackets and then made a simultaneous equation for real and imaginary part but I’m stuck here 1) a+3bi^2=25 2)abi+3i=-39i . I need a suggestion how should I make them into one equation

Presumably you know what i^2 is? :smile:
Reply 2
Original post by davros
Presumably you know what i^2 is? :smile:

-1 isn’t it? I figured out the question already but thanks
Two possible pairs of values for a & b
a,b = (18, - 7/3)
and
(7, - 6)

Combine the two equations into one and solve for the variables

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